Transformers

Transformer Equivalent Circuit: Parameters, Derivation & Model

Transformer equivalent circuit testing and parameter measurement on a large power transformer in a high-voltage test lab

Key takeaways

  • A transformer equivalent circuit models physical winding losses, magnetic leakage flux, core hysteresis, and eddy currents as lumped linear electrical components.
  • The magnetising branch (Rc and Xm) represents core losses and mutual flux, determined experimentally via the open-circuit test conducted at rated voltage.
  • Winding resistance (R1, R2) and leakage reactance (X1, X2) represent copper Joule losses and non-linking leakage flux, derived via the short-circuit test.
  • Referring secondary impedance values to the primary winding requires multiplying the ohmic values by the square of the turns ratio (a squared).
  • An approximate equivalent circuit shifts the shunt magnetising branch to the supply terminals, introducing less than 1% calculation error for distribution and power transformers under typical loads.

Quick answer: A transformer equivalent circuit is a lumped-parameter electrical schematic that models the real physical behaviour of a transformer—including winding resistance, leakage reactance, core magnetisation, and iron losses—referred to a single voltage level. It enables engineers to analytically calculate voltage regulation, fault currents, and operational efficiency without performing full-load laboratory testing.

In practical power system design, an ideal transformer calculation assuming zero internal losses and perfect magnetic coupling is insufficient. Physical transformers operating under IEC 60076 or IEEE C57.12.00 experience voltage drops under load due to winding impedance and consume active and reactive power even when unloaded. Developing an accurate transformer equivalent circuit allows power systems engineers, substation designers, and plant operators to predict transient responses, determine short-circuit duties, and optimise power distribution networks. For comprehensive thermal sizing and load profiles, refer to our transformer sizing calculator guide.

What Is a Transformer Equivalent Circuit?

A transformer equivalent circuit is an electrical network representation that models the active and reactive losses of magnetically coupled windings using standard circuit elements: resistors and inductors. The model isolates individual electromagnetic phenomena into discrete, measurable parameters.

In a real power transformer, energy transfer occurs through mutual electromagnetic induction across a laminated silicon steel or amorphous core. However, real-world operation deviates from the ideal transformer through four primary mechanisms:

  • Primary and secondary winding resistances ($R_1$ and $R_2$): Cause $I^2R$ copper losses (Joule heating) in the conductor coils under load.
  • Primary and secondary leakage reactances ($X_1$ and $X_2$): Represent leakage magnetic flux that links only one winding without traversing the core, creating an inductive reactive voltage drop.
  • Core loss resistance ($R_c$ or $R_{fe}$): Models the active real power dissipated in the core laminations due to magnetic hysteresis and circulating eddy currents.
  • Magnetising reactance ($X_m$ or $X_\phi$): Represents the reactive power required to establish the alternating mutual magnetic flux in the magnetic core path.

By arranging these elements systematically, engineers can evaluate performance across varied operating power factors and terminal loads using linear circuit analysis methods.

Exact vs Approximate Equivalent Ckt of Transformer

The exact equivalent ckt of transformer places the shunt magnetising branch between the primary winding impedance and the referred secondary winding impedance, whereas the approximate equivalent circuit shifts this shunt branch directly to the input terminals. This structural difference dictates the computational complexity and precision of grid load-flow calculations.

In the exact equivalent circuit, the primary current ($I_1$) splits into the exciting current ($I_0$) and the load component ($I_2'$). Consequently, the primary winding impedance ($R_1 + jX_1$) carries the full input current, producing a slight voltage drop that reduces the induced electromotive force ($E_1$) below the terminal voltage ($V_1$). Because $I_0$ is governed by $E_1$, the magnetising current technically depends on the operating load.

However, in standard distribution and transmission transformers, the no-load excitation current ($I_0$) typically represents only 1% to 3% of the rated full-load current. Consequently, the voltage drop across $R_1$ and $X_1$ caused by $I_0$ is negligible. Shifting the shunt branch ($R_c$ and $X_m$) directly to the supply input terminals forms the approximate equivalent ckt of transformer. This simplification allows engineers to combine the series primary and secondary impedances into single lumped parameters:

  • Equivalent series resistance: $R_{eq} = R_1 + R_2'$
  • Equivalent series reactance: $X_{eq} = X_1 + X_2'$
  • Total equivalent series impedance: $Z_{eq} = R_{eq} + jX_{eq}$

The calculation error introduced by this approximate model is typically below 1% for active power losses and terminal voltage calculations, making it the industry standard for commercial fault-level assessments and protective relay coordinate settings.

Referring Parameters: Primary and Secondary Side Formulas

Referring electrical parameters across a transformer involves scaling resistances, reactances, voltages, and currents by the turns ratio squared to account for magnetic coupling across differing voltage levels. This mathematical transformation eliminates the ideal transformer isolation stage from circuit calculations.

The transformation ratio, denoted as $a$, is defined by the winding turn numbers or the no-load phase voltage ratio, as detailed in our guide on the transformer turns ratio formula:

a = N1 / N2 = V1 / V2

To transfer secondary circuit quantities to the primary reference side, the following conversion relationships must be strictly applied:

  • Referred secondary voltage: V2' = a × V2
  • Referred secondary current: I2' = I2 / a
  • Referred secondary winding resistance: R2' = a2 × R2
  • Referred secondary leakage reactance: X2' = a2 × X2
  • Referred load impedance: ZL' = a2 × ZL

Conversely, when transferring primary parameters to the secondary voltage base, divide resistances and reactances by $a^2$, multiply currents by $a$, and divide voltages by $a$. For detailed multi-winding network derivations, consult our engineering guide on transformer impedance calculations.

Determining Parameters from Open-Circuit and Short-Circuit Tests

Equivalent circuit parameters are determined experimentally through standard no-load (open-circuit) and short-circuit factory acceptance tests conducted according to IEC 60076-1 and IEEE C57.12.90. These standard procedures isolate shunt core losses from series winding losses.

To obtain complete parameters, follow this systematic testing sequence as outlined in our manual on how to test a transformer:

  1. Perform the Open-Circuit (No-Load) Test: Apply rated line-to-line voltage to the low-voltage (LV) winding while leaving the high-voltage (HV) winding completely open-circuit. Record the open-circuit voltage ($V_{oc}$), no-load current ($I_{oc}$), and no-load active power loss ($P_{oc}$). Because the no-load current is minimal, series $I^2R$ drops are negligible, meaning $P_{oc}$ represents purely iron losses ($P_{fe}$).
  2. Calculate the Shunt Parameters: Determine the no-load power factor: $\cos(\phi_0) = P_{oc} / (V_{oc} \cdot I_{oc})$. Calculate the active core-loss current component: $I_c = I_{oc} \cdot \cos(\phi_0)$ and the magnetising component: $I_m = I_{oc} \cdot \sin(\phi_0)$. Derive core resistance $R_c = V_{oc} / I_c$ and magnetising reactance $X_m = V_{oc} / I_m$.
  3. Perform the Short-Circuit (Impedance) Test: Bolt the LV terminals together with a low-resistance shorting bar. Apply a reduced, variable AC voltage to the HV terminals, increasing slowly until rated full-load current ($I_{sc}$) circulates. Measure the short-circuit voltage ($V_{sc}$), test current ($I_{sc}$), and absorbed power ($P_{sc}$).
  4. Calculate the Series Parameters: Because the applied voltage is only 4% to 10% of rated voltage, the mutual core flux is tiny, rendering core losses negligible. Therefore, $P_{sc}$ represents total copper losses ($P_{cu}$). Calculate equivalent impedance: $Z_{eq} = V_{sc} / I_{sc}$; equivalent resistance: $R_{eq} = P_{sc} / (I_{sc}^2)$; and equivalent leakage reactance: $X_{eq} = \sqrt{Z_{eq}^2 - R_{eq}^2}$.
Test TypeMeasurement ParameterCalculated Circuit ElementPhysical MeaningTarget Winding Standard
Open-Circuit (No-Load)$V_{oc}, I_{oc}, P_{oc}$$R_c$ (Core Resistance, Ω)Hysteresis and eddy current lossUsually measured on LV winding
Open-Circuit (No-Load)$V_{oc}, I_{oc}, P_{oc}$$X_m$ (Magnetising Reactance, Ω)Permeability & core flux creationUsually measured on LV winding
Short-Circuit (Impedance)$V_{sc}, I_{sc}, P_{sc}$$R_{eq}$ (Equivalent Resistance, Ω)Ohmic Joule winding lossesUsually measured on HV winding
Short-Circuit (Impedance)$V_{sc}, I_{sc}, P_{sc}$$X_{eq}$ (Equivalent Reactance, Ω)Primary and secondary leakage fluxUsually measured on HV winding

Worked Engineering Example: Calculating Circuit Values for a 1000 kVA Transformer

A worked example demonstrating parameter derivation from actual factory test data verifies how raw wattmeter, voltmeter, and ammeter readings translate into the lumped circuit model. Consider a 1000 kVA, 11 kV to 415 V, 50 Hz, three-phase delta-wye distribution transformer evaluated per phase on a single-phase equivalent basis.

The factory acceptance test yields the following phase-to-neutral measurements on the single-phase base (rated single-phase apparent power $S_{1\phi} = 333.33\text{ kVA}$, primary phase voltage $V_1 = 11,000\text{ V}$, secondary phase voltage $V_2 = 240\text{ V}$):

  • No-Load Test (conducted on LV side, 240 V): $V_{oc} = 240\text{ V}$, $I_{oc} = 23.15\text{ A}$, $P_{oc} = 650\text{ W}$
  • Short-Circuit Test (conducted on HV side, rated current): $I_{sc} = 30.30\text{ A}$, $V_{sc} = 550\text{ V}$, $P_{sc} = 3800\text{ W}$

First, calculate turns ratio $a$:

a = 11,000 / 240 = 45.833

From the no-load test on the LV side:

  • No-load power factor: $\cos(\phi_0) = 650\text{ W} / (240\text{ V} \times 23.15\text{ A}) = 0.117$
  • $\sin(\phi_0) = \sqrt{1 - 0.117^2} = 0.993$
  • Core loss current: $I_c = 23.15 \times 0.117 = 2.71\text{ A}$
  • Magnetising current: $I_m = 23.15 \times 0.993 = 22.99\text{ A}$
  • LV core resistance: $R_{c(LV)} = 240\text{ V} / 2.71\text{ A} = 88.56\ \Omega$
  • LV magnetising reactance: $X_{m(LV)} = 240\text{ V} / 22.99\text{ A} = 10.44\ \Omega$

Referring the shunt branch to the primary HV side:

Rc(HV) = a2 × Rc(LV) = (45.833)2 × 88.56 Ω = 186,036 Ω (186.04 kΩ)

Xm(HV) = a2 × Xm(LV) = (45.833)2 × 10.44 Ω = 21,931 Ω (21.93 kΩ)

From the short-circuit test on the HV side:

  • Total equivalent series resistance: $R_{eq(HV)} = P_{sc} / I_{sc}^2 = 3800\text{ W} / (30.30\text{ A})^2 = 4.14\ \Omega$
  • Total equivalent series impedance: $Z_{eq(HV)} = V_{sc} / I_{sc} = 550\text{ V} / 30.30\text{ A} = 18.15\ \Omega$
  • Total equivalent series reactance: $X_{eq(HV)} = \sqrt{18.15^2 - 4.14^2} = 17.67\ \Omega$
  • Per-unit impedance (%Z): $(550\text{ V} / 11,000\text{ V}) \times 100 = 5.00\%$

Assuming standard symmetrical winding geometry, resistances and reactances split equally between primary and secondary windings: $R_1 = R_2' = 2.07\ \Omega$, and $X_1 = X_2' = 8.84\ \Omega$ referred to the high-voltage terminals.

Impact on Voltage Regulation and Efficiency Analysis

Voltage regulation and operating efficiency are direct mathematical functions of the series resistance and leakage reactance parameters derived in the transformer equivalent circuit. Variations in the load power factor dynamically alter terminal voltage drop and overall plant throughput.

Voltage regulation defines the percentage change in secondary terminal voltage magnitude between no-load and full-load conditions. Using the equivalent series parameters referred to the secondary winding, the approximate percentage voltage regulation ($VR\%$) for a load current ($I_2$) at terminal voltage ($V_2$) is expressed as:

VR (%) = [ (I2 × Req2 × cos(φ) ± I2 × Xeq2 × sin(φ)) / V2 ] × 100

In this equation, the plus sign applies to lagging inductive loads (such as induction motors), while the minus sign applies to leading capacitive loads (such as power factor correction banks). High leakage reactance ($X_{eq}$) causes severe voltage dips during heavy inductive surges, directly affecting motor starting torque and sensitive industrial electronics.

Transformer efficiency (η) balances fixed no-load core losses against variable copper load losses:

η = [ Pout / (Pout + Pcore + I22 × Req2) ] × 100

Maximum operating efficiency occurs when the variable load losses ($I_2^2 \times R_{eq2}$) equal the constant shunt core losses ($V_1^2 / R_c$). Industrial distribution transformers are deliberately engineered with high-permeability core steel to reach peak efficiency between 50% and 75% of continuous nameplate loading, matching average grid utility duty cycles.

Next steps: specifying and sourcing

Accurate equivalent circuit modeling ensures electrical distribution equipment operates reliably under varying thermal, mechanical, and transient grid conditions. When preparing design briefs or engineering requisitions, provide prospective manufacturers with your system rated kVA, primary/secondary operating voltages, vector group, target percent impedance (%Z per IEC 60076 or IEEE C57.12), and guaranteed loss limits.

Explore our heavy-duty power transformer line for high-voltage transmission networks, review our efficient oil-immersed transformer range for utility distribution, or specify our fire-safe dry-type transformer units for indoor commercial substations. For technical support, custom impedance design, and factory testing documentation, submit your project requirements directly through our request a quotation page to consult with our applications engineering team.

Frequently asked questions

Why is the transformer equivalent circuit necessary?

It allows electrical engineers to calculate voltage drop, fault currents, and operating efficiency analytically without testing the unit under full physical load. The circuit models physical winding resistance, core losses, and magnetic leakage as standard linear electrical components.

What is the difference between exact and approximate equivalent circuits?

The exact circuit places the shunt magnetising branch between the primary and secondary series impedances, whereas the approximate circuit moves the shunt branch directly to the input terminals. The approximate model simplifies calculations while introducing less than 1% error in most commercial distribution applications.

Which parameters are obtained from the open-circuit test?

The open-circuit test determines core loss resistance (Rc) and magnetising reactance (Xm), representing magnetic hysteresis, eddy current losses, and core permeability. It is typically conducted by energising the low-voltage winding at rated voltage while the high-voltage winding remains open.

Which parameters are obtained from the short-circuit test?

The short-circuit test determines the total equivalent winding resistance (Req) and total equivalent leakage reactance (Xeq). It measures full-load copper losses and leakage flux impedance by applying a reduced circulating voltage to the high-voltage terminals while the low-voltage terminals are shorted.

How do you refer secondary impedance to the primary side?

Multiply the secondary resistance and reactance values by the square of the turns ratio (a squared), where a = N1 / N2. This scales the ohmic values to maintain equivalent active and reactive power dissipation across differing voltage ratings.

What does leakage reactance represent in a transformer?

Leakage reactance represents the voltage drop caused by magnetic flux lines that pass through only one winding and close through the air or insulation without linking the other winding. It acts as a series inductive reactance restricting both load current and through-fault short-circuit levels.

Tags: transformer equivalent circuit equivalent ckt of transformer transformer impedance open circuit test short circuit test

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